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x^2+3x-28=3*742
We move all terms to the left:
x^2+3x-28-(3*742)=0
We add all the numbers together, and all the variables
x^2+3x-28-2226=0
We add all the numbers together, and all the variables
x^2+3x-2254=0
a = 1; b = 3; c = -2254;
Δ = b2-4ac
Δ = 32-4·1·(-2254)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9025}=95$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-95}{2*1}=\frac{-98}{2} =-49 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+95}{2*1}=\frac{92}{2} =46 $
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